The heat loss is calculated by multiplying the liquid flow rate, density, specific heat, temperature rise, and correction factor. The factor of 60 converts from gallons per minute to gallons per hour.

\begin{equation}\label{eq:liquid-cooling-heat-loss} Q_\text{cool} = FR \cdot 60 \cdot \rho_{l,lb/ft^3} \cdot SH \cdot \Delta T \cdot CF\end{equation}

Symbols

\(Q_\text{cool}\)	Liquid cooling heat loss \([\unit{ \btu\per\hour}]\)
\(FR\)	Liquid flow rate \([\unit{ \gallon\per\minute}]\)
\(60\)	Minutes per hour (GPM to GPH conversion) - see physics::conversions::kMinutesPerHour \([\unit{ \unitless}]\)
\(\rho_{l,lb/ft^3}\)	Liquid density \([\unit{ \pound\per\cubicFoot}]\)
\(SH\)	Specific heat of liquid \([\unit{ \btu\per\pound\degreeFahrenheit}]\)
\(\Delta T\)	Temperature rise (outlet - inlet) \([\unit{ \degreeFahrenheit}]\)
\(CF\)	Correction factor \([\unit{ \unitless}]\)